3.3.11 \(\int \frac {a+b x^3}{x^2} \, dx\) [211]

Optimal. Leaf size=15 \[ -\frac {a}{x}+\frac {b x^2}{2} \]

[Out]

-a/x+1/2*b*x^2

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Rubi [A]
time = 0.00, antiderivative size = 15, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {14} \begin {gather*} \frac {b x^2}{2}-\frac {a}{x} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a + b*x^3)/x^2,x]

[Out]

-(a/x) + (b*x^2)/2

Rule 14

Int[(u_)*((c_.)*(x_))^(m_.), x_Symbol] :> Int[ExpandIntegrand[(c*x)^m*u, x], x] /; FreeQ[{c, m}, x] && SumQ[u]
&&  !LinearQ[u, x] &&  !MatchQ[u, (a_) + (b_.)*(v_) /; FreeQ[{a, b}, x] && InverseFunctionQ[v]]

Rubi steps

\begin {align*} \int \frac {a+b x^3}{x^2} \, dx &=\int \left (\frac {a}{x^2}+b x\right ) \, dx\\ &=-\frac {a}{x}+\frac {b x^2}{2}\\ \end {align*}

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Mathematica [A]
time = 0.00, size = 15, normalized size = 1.00 \begin {gather*} -\frac {a}{x}+\frac {b x^2}{2} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(a + b*x^3)/x^2,x]

[Out]

-(a/x) + (b*x^2)/2

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Maple [A]
time = 0.02, size = 14, normalized size = 0.93

method	result	size
default	\(-\frac {a}{x}+\frac {b \,x^{2}}{2}\)	\(14\)
risch	\(-\frac {a}{x}+\frac {b \,x^{2}}{2}\)	\(14\)
norman	\(\frac {\frac {b \,x^{3}}{2}-a}{x}\)	\(15\)
gosper	\(-\frac {-b \,x^{3}+2 a}{2 x}\)	\(16\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x^3+a)/x^2,x,method=_RETURNVERBOSE)

[Out]

-a/x+1/2*b*x^2

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Maxima [A]
time = 0.29, size = 13, normalized size = 0.87 \begin {gather*} \frac {1}{2} \, b x^{2} - \frac {a}{x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^3+a)/x^2,x, algorithm="maxima")

[Out]

1/2*b*x^2 - a/x

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Fricas [A]
time = 0.33, size = 14, normalized size = 0.93 \begin {gather*} \frac {b x^{3} - 2 \, a}{2 \, x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^3+a)/x^2,x, algorithm="fricas")

[Out]

1/2*(b*x^3 - 2*a)/x

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Sympy [A]
time = 0.02, size = 8, normalized size = 0.53 \begin {gather*} - \frac {a}{x} + \frac {b x^{2}}{2} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x**3+a)/x**2,x)

[Out]

-a/x + b*x**2/2

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Giac [A]
time = 1.68, size = 13, normalized size = 0.87 \begin {gather*} \frac {1}{2} \, b x^{2} - \frac {a}{x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^3+a)/x^2,x, algorithm="giac")

[Out]

1/2*b*x^2 - a/x

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Mupad [B]
time = 0.02, size = 13, normalized size = 0.87 \begin {gather*} \frac {b\,x^2}{2}-\frac {a}{x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*x^3)/x^2,x)

[Out]

(b*x^2)/2 - a/x

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